jmferraro: I believe this is wrong and white has only 21 liberties. First case : no T shape sehnanigans : 6 * 3 prongs + 2*1 simple liberits + 1 T that is filled last = 21. With T shape exchange suggested by hoshi911 : 4 T liberties + 2 *1 simple + 5 * 3 prongs + 1prong filled last - 2 investe moves on T = 20. so 21 is the answer. Katago seems to agree that white is dead
SouthernGoPlayer: This seems way off. The solution claims identical numbers of liberties or closely matching, however it appears to be miss counting the false eyes as two liberties where they should be 3 or mostly 3. If the no eye group ends up with multiple ko's in playing out this race then they are able to start a perpetual ko at worst, no?
d4rkm4tter: Never be overconfident at things like this, but I'm very sure the count is always correct now.
hoshi911: solution counts one liberty less for white as it in fact has.
In particular, white's T-shape at the top is worth 2 liberties, not
just one:
white can force J13, black needs to answer J15, and when white invests
another two stones at J14 and J15, the T-shape with additionally 4
liberties is connected. So 4 liberties - 2 moves invested = 2 liberties.
d4rkm4tter: Wow. That makes it even more tricky. I modified the problem.
Never be overconfident at things like this, but I'm very sure the count is always correct now.